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4.9x^2+22x-381=0
a = 4.9; b = 22; c = -381;
Δ = b2-4ac
Δ = 222-4·4.9·(-381)
Δ = 7951.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-\sqrt{7951.6}}{2*4.9}=\frac{-22-\sqrt{7951.6}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+\sqrt{7951.6}}{2*4.9}=\frac{-22+\sqrt{7951.6}}{9.8} $
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